What is the synchronous speed of a four pole, 60 Hz single phase motor?

What is the synchronous speed of a four pole, 60 Hz single phase motor?

• A. 3600 rpm
• B. 1800 rpm
• C. 1200 rpm
• D. 2400 rpm

Answer: (B)

The synchronous speed of an AC motor can be calculated using the formula: Synchronous Speed (RPM) = (120 x Frequency) / Number of Poles. In the case of a four-pole motor running at a frequency of 60 Hz, the calculation would proceed as follows: 1. Multiply 120 by the frequency: 120 x 60 = 7200. 2. Divide the result by the number of poles: 7200 / 4 = 1800 RPM. Therefore, the synchronous speed of a four-pole, 60 Hz motor is 1800 RPM. This speed is significant because it represents the speed at which the magnetic field rotates in the stator, and understanding this concept is essential for determining the operation and efficiency of AC motors in HVAC systems.

The synchronous speed of an AC motor can be calculated using the formula:

Synchronous Speed (RPM) = (120 x Frequency) / Number of Poles.

In the case of a four-pole motor running at a frequency of 60 Hz, the calculation would proceed as follows:

1. Multiply 120 by the frequency: 120 x 60 = 7200.

2. Divide the result by the number of poles: 7200 / 4 = 1800 RPM.

Therefore, the synchronous speed of a four-pole, 60 Hz motor is 1800 RPM. This speed is significant because it represents the speed at which the magnetic field rotates in the stator, and understanding this concept is essential for determining the operation and efficiency of AC motors in HVAC systems.